Find the least number of six digit which is exactly divisible by 15 21 and 28
Answers
Answered by
13
15=3×5
21=3×7
28=2×2×7
LCM(15,21,28)=Product of greatest power of each factor
=2×2×5×7×3
=420
The number which is exactly divusible by 15,21 and 28 also must be divisible by 420
Least 6-digit number is 1,00,000
On dividing 1,00,000 by 420 we get :-
40 as remainder
Hence,the required number=1,00,000+(420-40)
=1,00,000+380
=1,00,380 Ans.
21=3×7
28=2×2×7
LCM(15,21,28)=Product of greatest power of each factor
=2×2×5×7×3
=420
The number which is exactly divusible by 15,21 and 28 also must be divisible by 420
Least 6-digit number is 1,00,000
On dividing 1,00,000 by 420 we get :-
40 as remainder
Hence,the required number=1,00,000+(420-40)
=1,00,000+380
=1,00,380 Ans.
Answered by
0
Answer:
ok biro scout is pro mortal is noob rega is lub
Step-by-step explanation:
Similar questions