Question

Find the least number of square tiles by which the floor of a room of dimensions 16.58 m and 8.32 m can be covered completely. please tell i will wait for the answer this is my humble request please answer the question please

Answer 1

Step-by-step explanation:

We require the least number of square tiles, hence each tile must be of maximum dimensions.

Hence, the maximum dimensions of a tile = HCF of 16.58 m and 8.32 m

Now, 16.58 m = 16.58 × 100 cm = 1658 cm

8.32 m = 8.32 × 100 cm = 832 cm

Hence, the side of a square tile = 2 cm

∴ Required number of tiles =Area of floorArea of a square tile

Required number of tiles =1658 × 832= 3448642 × 2

Answer 2

Answer:

344864 tiles are required.

Step-by-step explanation:

Dimensions of the room = 16.58 m and 8.32 m

Dimensions of the square tile = ??  

Convert the dimensions of room into centimeter.

⇒ 16.58 × 100 ---- (1 m = 100 cm)

⇒ 1658 cm

⇒ 8.32 × 100 ---- (1 m = 100 cm)

⇒ 832 cm

____________________________

The HIGHEST COMMON FACTOR of 1658 and 832 is the side of tile.

Factors of 1658 = 2 × 829

Factors of 832 = 2 × 2 × 2 × 2 × 2 × 2 × 13

HCF is 2.

The side of the square shaped tile is 2 cm

____________________________

Number of tiles required = $\sf{\dfrac{ Area\:of\:room}{Area\:of\:tile}$

Area of room = Length × Breadth

⇒ 1658 × 832

⇒ 1379456 cm²

Area of tile = Side × Side

⇒ 2 × 2

⇒ 4 cm²

Number of tiles =

⇒ $\sf\dfrac{1379456}{4}$

⇒ 344864

Therefore, 344864 tiles are required.