Question

find the least number of square tiles required to pave the ceiling of a room 15m 17cm long and 9 m 2cm broad

Answer 1

lenght of the room=15m 17cm=
15×100+17=1517
breadth=9m2cm=902 cm
the HCF of the 1517 and 902 will be size of saure tiles
HCF 1517 and 902 = 41cm
area of room= leanth×breadth=1517×902cm²
area of tiles=41×41cm²1
so num. of tiles required(1517×902)(41×41)
=814 tiles

Answer 2

Lenghth of the room;

15m 17cm=15×100+17=1517

Breadth=9m2cm=902 cm

The HCF of the 1517 and 902 will be size of saure tiles

HCF 1517 and 902 = 41cm

area of room= length×breadth=1517×902cm²

area of tiles=41×41cm²1

so num. of tiles required;

=(1517×902)(41×41)

=814 tiles