Question

find the least number of square tiles required to pave the floor of a hall 20m 20cm long and 12m 40cm broad.

Answer 1

Given length of hall = 20m 20cm = 2020cm.

Given breadth of hall = 12m 40cm = 1240cm.

Now,

The size of square tiles will be the HCF of 2020 and 1240.

= > HCF of 2020 and 1240 = 2 * 2 * 5 = 20cm.

Now,

Area of each tile = 20 * 20

= > 400 cm^2.

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The required number of tiles = Area of hall/Area of each tile

= > (2020 * 1240)/400

= > 6262.

Hope this helps!

Answer 2

Length of the room = 20 m 20 cm = 20*100 + 20 = 2020 cm.

Breadth of the room = 12 m 40 cm = 12*100 + 40 = 1240 cm.

The HCF of the 2020 and 1240 will be size of square tiles.

HCF 2020 and 1240 = 20 cm.

Area of the room = length * breadth = 2020 * 1240 cm2.

Area of tiles = 20*20 cm2

So, no. of tiles required = (2020*1240)/(20*20) = 6262 tiles