Math, asked by sauravoutlook, 9 months ago


Find the least number of square tiles which can cover the floor of a rectangula
shape having length and breadth 16 metres 58 centimetres and 8 metre
32 centimetres respectively.

Answers

Answered by ayushidhiman88
2

Step-by-step explanation:

length of the floor = 15m 17cm

                              =1517cm

breadth of the floor = 8m 32cm

                                = 832 cm

HCF of length and breadth of floor = side of a square tile

                                                          = 2 cm

area of floor = l * b = 1517 * 802 cm^2

area of square tile = a * a = 2*2 cm^2

number of tiles = area of floor/area of square tile

                         = 1517*832/2*2

may it help u ♥️

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