Question

find the least number that being increased by 8 is divisible by 32 36 and 40

Answer 1

first of all you take the LCM of 32 36 and 40.
you will find 1440 then the number will be 1440 - 8= 1432

Answer 2

The required least number is 1432

Given :

The numbers 32 , 36 and 40

To find :

The least number that being increased by 8 is divisible by 32 , 36 and 40

Solution :

Step 1 of 2 :

Calculate LCM of 32 , 36 and 40

On prime factorisation

32 = 2 × 2 × 2 × 2 × 2

36 = 2 × 2 × 3 × 3

40 = 2 × 2 × 2 × 5

∴ LCM of 32 , 36 and 40

= 2 × 2 × 2 × 2 × 2 × 3 × 3 × 5

= 1440

Step 2 of 2 :

Find the number

Since the required number is the least number that being increased by 8 is divisible by 32 , 36 and 40

Hence the required number

= 1440 - 8

= 1432

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