Math, asked by jiyagandhi015, 14 hours ago

find the least number that is exactly divisble by 72 and 81​

Answers

Answered by itzmedipayan2
2

Answer:

You are looking for the Lowest Common Denominator, LCD.

Firstly, compute the prime factors of both 72 and 96, respectively.

72 = 24 x 3 = 8 x 3 x 3 = 2 x 2 x 2 x 3 x 3

96 = 24 x 4 = 8 x 3 x 4 = 2 x 2 x 2 x 3 x 2 x 2

To form the LCD, we need to combine the least number of both sets of prime factors so both numbers are represented:

LCD = 2 x 2 x 2 x 3 x 3 x 2 x 2 = 288.

Thus 288 is the smallest number that is divisible by both 72 and 96.

Answered by gaurianushka987
0

Step-by-step explanation:

here is your answer

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