Math, asked by siddharthdullu2141, 1 year ago

Find the least number that must be added to 49123 to get a number exactly divisible by 263

Answers

Answered by Anonymous

let us first check what is the remainder
49123=263×1+205

so remainder is 205
so -205 should be added to 49123 to make it exactly divisible
let's verify
49123+(-205)=48918

263×186=48918
hence verified

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