Question

Find the least number that must be subtracted to 6666 so that it becomes a perfect square,
Also find the square root of the perfect square thus obtained.


answer me briefly plsssssss​

Answer 1

Answer:

the least no. to be subracted is 105. and the square root of the new no. is 81.

Step-by-step explanation:

First, lets find the square root of 6666 by using division method

√6666

So remainder=105

now lets subract 105 from 6666

6666 subracted from 105=6561

and therefore √6561=81

Answer 2

SOLUTION :

LCM of 6666 = 2*3*(11*11)

( here, the number which is in bracket is considered as a whole for example (2*2) when we will remove the bracket we shall write just a 2 )

Therefore, the number by which 6666 should be divided in other to make it a perfect square = 2*3 = 7
—————————————-
• The perfect square= 6666 divided by 6
= 1111 ( ANSWER )
—————————————
The square root of 1111 -
1111 by prime factorisation gives,
= (11*11)
= 11 ( ANSWER )
—————————————

Hope it would help you,
Have a nice day!
:D