Question

Find the least number that should be added to 5046 so that the sum is exactly divisible by 5,4,6 and 3

Answer 1

since the no should be divisible 5,4,6,3 hence it should be divisible by there multiple also which is 360....now divide 5046 by 360 we get 6 as remainder ...we can subtract 6 from it to make it divisible by 360 but since we have to add me subtract 360-6 that is 354...it is

Answer 2

The least number that should be added to 5046 so that the sum is exactly divisible by 5,4,6 and 3 is 54.

Step-by-step explanation:

To find : The least number that should be added to 5046 so that the sum is exactly divisible by 5,4,6 and 3 ?

Solution :

First we take LCM of 5,4,6 and 3 .

2 | 3  4  5  6

2 | 3  2  5  3

3 | 3  1   5  3

5 | 1   1   5   1

  | 1   1   1   1

$LCM(3,4,5,6)=2\times 2\times3\times 5$

$LCM(3,4,5,6)=60$

Divide 5046 by 60 so that we get the remainder,

$5046 =60 \times 84+6$

Remainder is 6.

The number should be added is 60-6=54

Therefore, the least number that should be added to 5046 so that the sum is exactly divisible by 5,4,6 and 3 is 54.

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Find the least number that should be added to 5046 so that sum is exactly divisible by 5,6,4,and 3

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