Find the least number that when devided by 16,18 and 20 leaves a remainder 4 in each case but is completlely divisible by 7
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Heya user,
The no. is of the form --> [ multiple of LCM of (16,18,20) ] + 4
Now,
LCM [ 16,18,20 ] = 720;
Hence, our no. is of the form 720x + 4;
Now, 7 | 720x + 4 => 7 | 7(102x) + 6x + 4 => 7 | 6x + 4;
Therefore, least value of x for which 7 | 6x + 4 ----> is 'x' = 4
Thus, the req.d no. is 720(4) + 4 = 2884..... ☺
The no. is of the form --> [ multiple of LCM of (16,18,20) ] + 4
Now,
LCM [ 16,18,20 ] = 720;
Hence, our no. is of the form 720x + 4;
Now, 7 | 720x + 4 => 7 | 7(102x) + 6x + 4 => 7 | 6x + 4;
Therefore, least value of x for which 7 | 6x + 4 ----> is 'x' = 4
Thus, the req.d no. is 720(4) + 4 = 2884..... ☺
Answered by
1
the number is 2884....
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