find the least number when divided by 12 , 15 , 20, and 54 in each case leaves a remainder of 8.
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Find the l.c.m of 12,15,20,54
12 = 2^2 * 3
15 = 3*5
20=2^2 * 5
54 = 2* 3^3
l.c.m = 2^2 * 3^3 * 5 = 540
Add 8 to the l.c.m== 540 + 8 = 548
Hence, 548 is the least number which when divided by 12,15,20,54 leaves a remainder '8'
Hope it helps.
12 = 2^2 * 3
15 = 3*5
20=2^2 * 5
54 = 2* 3^3
l.c.m = 2^2 * 3^3 * 5 = 540
Add 8 to the l.c.m== 540 + 8 = 548
Hence, 548 is the least number which when divided by 12,15,20,54 leaves a remainder '8'
Hope it helps.
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