find the least number when divided by 12 ,leaves a remainder of 7,when divided 15 ,leaves a remainder of 10 and when divided by 16 leaves a remainder of 11.
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Answer is 235
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12=2
2
×3
15=3×5
16=2
4
LCM=2
4
×3×5=240
Now, the number has a remainder of 7 when divided by 12. Similarly, number has remainder 10 on dividing by 15 and remainder is 11 when divided by 16. In each case, we are 5 short of getting a zero remainder. So the desired number must be 240−5=235
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