Math, asked by ShadowCain8756, 1 year ago

Find the least number when divided by 25 45 and 60 leaves a remainder of 20

Answers

Answered by ravitata14
88
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Answered by payalchatterje
1

Answer:

The least number when divided by 25 45 and 60 leaves a remainder of 20 is 920.

Step-by-step explanation:

The given numbers are 25,45,60.

The smallest number which when divided by 25,45 and 60 leaves remainder 20 is obtained by adding 7 to the L.C.M of 25,45,60.

By prime factorisation of 25

 = 5 \times 5

Prime factorization of 45

 = 5 \times 3 \times 3

Prime factorization of 60

 = 2 \times 2 \times 3 \times 5

So,LCM of 25,45 and 50

 = 5 \times 5 \times 3 \times 3 \times 2 \times 2 \ \\  = 25 \times 9 \times 4 \\  = 900

Therefore smallest number which when divided by 25,45,60 leaves same remainder 20  = 900 + 20 = 920

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