find the least number which after being increased by 2 is exactly divisible by 8, 16 and 24
Answers
Answered by
23
2 is the minimum number which when increased by 2 is exactly divisible by 8, 16 and 24.
Answered by
28
Given integers,
8 , 16 and 24
Prime factorization of,
8=2³
16=2⁴
24=2³×3
LCM=product of each prime factor of highest power.
LCM=2⁴×3=48
Required number=48-2=46
Hence least number which after being increased by 2 is exactly divisible by 8 , 16 and 24 is 46.
8 , 16 and 24
Prime factorization of,
8=2³
16=2⁴
24=2³×3
LCM=product of each prime factor of highest power.
LCM=2⁴×3=48
Required number=48-2=46
Hence least number which after being increased by 2 is exactly divisible by 8 , 16 and 24 is 46.
Similar questions