find the least number which after being increased by 2 is exactly divisible by 8 16 and 24
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Answer:
So , LCM of 8 , 16 and 24 = 2 × 2 × 2 × 2 × 3 = 48 Now , required number = 48 - 2 = 46 So , 46 is the required least number that after being increased by 2 becomes exactly divisible by 8 , 16 and 24
Answered by
1
Answer:
First find LCM of 8,16 and 24 i.e. 48.
Now subtract 2 from 48 i.e. 46. 46 is answer because when it's increased by 2 its exactly divisible by 8, 16 and 24.
Hope it helps you dear friend.
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