Question

find the least number which becomes exactly divisible by 16,28,40 and 77 when 29 is added to it

Answer 1

becomes to exactly divedid for answer=7

Answer 2

Answer:

The least number which becomes exactly divisible by 16,28,40 and 77 when 29 is added to it is 6189.

Step-by-step explanation:

To find : The least number which becomes exactly divisible by 16,28,40 and 77 when 29 is added to it?  

Solution :  

We find the LCM of 16,28,40 and 77.

2 | 16  28  40   77

2 |  8   14   20   77

2 |  4    7    10   77

2 |  2    7     5   77

5 |  1     7     5   77

7 |  1     7     1    77

11 |  1     1     1    11

  |  1     1      1    1

$LCM(16,28,40,77)=2\times 2\times 2\times 2\times 5\times 7\times 11$  

$LCM(16,28,40,77)=6160$  

When 29 is added.

i.e. 6160+29=6189.

Therefore, The least number which becomes exactly divisible by 16,28,40 and 77 when 29 is added to it is 6189.