Find the least number which can diveded by 12, 16, 24, 36 leaves a remainder 3 in each a case
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Least number when divided by 12,16,24,36 and leaves remainder 0
=LCM of 12,16,24,36
So,LCM leaves remainder 0
So,Required number will be 7 more than LCM
∴ Required number=LCM+7
Factors of 12=2×3×2
Factors of 16=2×2×2×2
Factors of 24=2×2×2×3
Factors of 36=2×2×3×3
∴ LCM=2×2×2×2×3×3=16×9=144
So,Required number=LCM+7=144+7=151
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