Find the least number which divided by
12, 16, 24 and 36 leaves a remainder 5 in each
case
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Answer:
144
Step-by-step explanation:
The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
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