find the least number which divided by 12 16 24 and 36 leaves a remanider 5 in each case
Answers
Answer:
For this particular sum we need to find the LCM of the given numbers. The smallest number which divides 12 16 24 and 36 is 144
Step-by-step explanation:
Least number when divided by 12,16,24,36 and leaves remainder 0
=LCM of 12,16,24,36
So,LCM leaves remainder 0
So,Required number will be 7 more than LCM
∴ Required number=LCM+7
Factors of 12=2×3×2
Factors of 16=2×2×2×2
Factors of 24=2×2×2×3
Factors of 36=2×2×3×3
∴ LCM=2×2×2×2×3×3=16×9=144
So,Required number=LCM+7=144+7=151
Màrk me brainlist
Answer:
the least number is 149
because the least number divisible by all the 4 numbers:- 12,16,24,36 is 144
therefore when we add 5 to it, it becomes 149
and dividing 149 from all the 4 numbers we get 5 as a remainder in all cases.
there fore, 149 is the least number divisible by all the 4 number leaves 5 as a remainder.
hope it helps...