Question

find the least number which divided by 12 16 24 and 36 leaves a remanider 5 in each case​

Answer 1

Answer:

For this particular sum we need to find the LCM of the given numbers. The smallest number which divides 12 16 24 and 36 is 144

Step-by-step explanation:

Least number when divided by 12,16,24,36 and leaves remainder 0

=LCM of 12,16,24,36

So,LCM leaves remainder 0

So,Required number will be 7 more than LCM

∴ Required number=LCM+7

Factors of 12=2×3×2

Factors of 16=2×2×2×2

Factors of 24=2×2×2×3

Factors of 36=2×2×3×3

∴ LCM=2×2×2×2×3×3=16×9=144

So,Required number=LCM+7=144+7=151

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Answer 2

Answer:

the least number is 149

because the least number divisible by all the 4 numbers:- 12,16,24,36 is 144

therefore when we add 5 to it, it becomes 149

and dividing 149 from all the 4 numbers we get 5 as a remainder in all cases.

there fore, 149 is the least number divisible by all the 4 number leaves 5 as a remainder.

hope it helps...