Question

Find the least number which divided by 40 50 and 60 leaves remainder 5 in each case ​

Answer 1

The required number

=LCM(40,50,60)+5

=10×4×3×5=600+5=605

if this helps you

mark as brainlest answer

Answer 2

Step-by-step explanation:

first we have to find lcm

[tex]2 |40 \: 50 \: 60| \\ 2 |20 \: 25 \: 30| \\ 2 |10 \: 25 \: 15| \\ 5 |5 \: 25 \: 15| \\ 5 |1 \: 5 \: 3| \\ 3 |1 \: 1 \: 3| ]

now lcm = 2×2×2×5×5×3= 600

now subtract 600 with 5

=600-5

= 595 is the answer.

pls mark me as brainliest.