Find the least number which divided by 98 and 105 will leave in each case the same remainder 10
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Step-by-step explanation:
Now taking the LCM of 98 and 105;
It is 2*3*5*7*7=1470;
As per the question by dividing the number by 98 and 105, get 10 as remainder;
So adding 10 in to 1470;1
1470+10=1480; Is the number which will leave a 10 remainder in both the case.
15*98+10=1480
14*105+10=1480
1470 is completely divisible by 98 and 105
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