Question

Find the least number which divides 20, 25 and 50 leaving a remainder of 9.​

Answer 1

Answer:

1

cause the HCF of 11, 16 and 51 is 1.... 11, 16 and 51 are the terms got by subtracting 9 from 20, 25 and 50.

hope this helps.....

Answer 2

Smallest number which is divisible by 20, 25 and 50 will be their LCM which is 100.

So the smallest number which divides by 20 25 50 leaving remainder 9​ will be
100 + 9 = 109

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