Find the least number which divisible by 6 15 and 18 leaves remainder 5 in each case
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multiples of
6- ....60,66,72,78,84,90
15-.15,30, 45, 60, 75, 90
18-18, 36,54,72,90,108
LCM-90
adding 5 to 90
=) 90+5= 95
so, if we divide 95 by 6, 15 or 18 we will get 5 as remainder in each case.
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