Find the least number which is a
multiple of 5, but when it is
divided by 18, 21, 24 the remainders
are 7,10 and 13 is resp.
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Answer:
Here (18 - 7) = 11, (21 - 10) = 11, (24 - 13) = 11
LCM of 18, 21 and 24 is 504
Let the required number be 504k - 11
Least value of k for which (504k - 11) is divisible by 23 is k = 6
∴ Required number
= 504 × 6 - 11
= 3024 - 11
= 3013
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