Find the least number which is divided by 12, 15 and 21
which leaves the remainder 3 in each case.
Answers
Answered by
1
The answer is 3.
3×4=12
3×5=15
3×7=21...
please support me
I hope it will help you
Answered by
0
The answer is 3 becuz 3x3=9 leaving a reminder of three,3x4=12 also leaving a reminder of 3 and 3x6=18 also leaving a reminder of 3. Hope it helps u.thx
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