Question

Find the
least number which is
divisible by 6, 7, 8, 9, 10,12 and leaves remainder 1 in
Each ( Cese.​

Answer 1

Step-by-step explanation:

Writing the prime factorization:

6=2×3  

7=1×7  

8=2×2×2  

9=3×3

12=2×2×3

the least common multiple therefore is:

2×7×2×2×3×3=504

So numbers which on being divided by 6,7,8,9 and 12 leave a remainder 1 are : 504+1=505

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