Find the least number which is exactly divisible by 20,28 and 32
Answers
Answered by
2
Answer:
when they least in the LCM and HCF problem's.we want to do LCM
LCM of 20,28and 32=448
Answered by
1
Answer:
1120
Step-by-step explanation:
least number divisible by 20 , 28 , 32 = LCM of 20, 28, 32
20 = 5¹ × 2²
28 = 7¹ × 2²
32 = 2⁵
LCM = Product of greatest power of each prime factor
= 7 × 5 × 2⁵
= 7 × 5 × 2 × 2 × 2 × 2 × 2
= 1120
Similar questions