Question

Find the least number which is exactly divisible by 31 but when divided by 15,24 and 32 leave the remainder 2,11 and 19 respectively

Answer 1

Hey Mate!!!

This is the answer

77*31 = 2387

2387/15 = 159.133 ( 159*15 = 2385) 2387–2385 =2

2387/24 = 99.458 ( 99*24 = 2376) 2387–2376 =11

2387/32 = 74.594 ( 74*32 = 2368) 2387–2368 =19

Hope it helps...

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