Math, asked by mohindramonika7, 6 months ago

Find the least number which is exactly divisible by 9 12 15 and 18 and leaves a remainder 1 in each case

Answers

Answered by KashviSaha

Answer:

361

Step-by-step explanation:

add 1 in the LCM of the numbers. 360+1=361. Therefore, the least number which when divided by 8, 9, 12 and 15 leaves a remainder of one in each case is 361.

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Find the least number which is exactly divisible by 9 12 15 and 18 and leaves a remainder 1 in each case​

Answers

Find the least number which is exactly divisible by 9 12 15 and 18 and leaves a remainder 1 in each case