find the least number which is when divisible by 8,12,14,36 and leaves a remainder 5 in each case?
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Hello there!
Here's the answer:
Type of problem:
To find Least No. which when divided by x,y,z leaves the same remainder 'r' in each case
Approach to problem:
Step:1 - Find LCM of x, y & z
Step:2- The required no. is then given by
Required No. = LCM(x,y,z) + r
Now,
To your question:
•Find LCM(8,12,14,36)
• Add it to the remainder '5' to get the required No.
LCM(8,12,14,36)= 504
Required No.= 504+ 5= 509
You can verify answer by dividing 509 by 8,12,14,36. The remainder will be 5.
;)
Hope it helps
Here's the answer:
Type of problem:
To find Least No. which when divided by x,y,z leaves the same remainder 'r' in each case
Approach to problem:
Step:1 - Find LCM of x, y & z
Step:2- The required no. is then given by
Required No. = LCM(x,y,z) + r
Now,
To your question:
•Find LCM(8,12,14,36)
• Add it to the remainder '5' to get the required No.
LCM(8,12,14,36)= 504
Required No.= 504+ 5= 509
You can verify answer by dividing 509 by 8,12,14,36. The remainder will be 5.
;)
Hope it helps
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