Find the least number which leaves remainder 1 when divided by 18 or 24 or 30
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Least common number of 18, 24 and 30 being 360 , since 18 = 2 x 3 x x 3, 24 = 2 x 2 x 2 x 3 and 30 = 2 x 3 x 5, so lcm is 2 x 2 x 2 x 3 x 3 x 5 = 360, THUS NIMBER 360 is divisible by any of the numbers 18, 24 or 30 with O remainder, therfore next higher number by adding 1 in 360, that is number 361 when divided by any of the numbers 18 or 24 or 30 will spare 1 in the remainder. Ans : 361
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least number is 18, 34,20
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