Question

Find the least number which leaves remainder 1 when divided by 2, 3, 4, 5 or 6 but is
completely divisible by 7.​

Answer 1

Answer:

QUESTION :-

Find the least number which leaves remainder 1 when divided by 2, 3, 4, 5 or 6 but iscompletely divisible by 7.

ANSWER :-

The least common multiple of 2, 3, 4, 5, 6 is their LCM=60.

So, the answer is the least number such that it is a multiple of 7 and a multiple of 60 leaving remainder 1.

∴The required answer is 301.

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Answer 2

Answer:

301 is the least no. and is completely divisible by 7 that is 43

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