Question

Find the least number which
must be added to 3064520
so as to get a perfet square
Aso find the squard rooth
perfect squase .
the
of​

Answer 1

Answer:

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Step-by-step explanation:

Solution:

Solution:(i) 525

Solution:(i) 525Since remainder is 41.

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923 2

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923 2 =529

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923 2 =529Hence, number to be added

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923 2 =529Hence, number to be added= 529 – 525 = 4

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923 2 =529Hence, number to be added= 529 – 525 = 4\therefore525+4=529∴525+4=529

Solution:(i) 525Since remainder is 41.Therefore 22^2<52522 2 <525Next perfect square number 23^2=52923 2 =529Hence, number to be added= 529 – 525 = 4\therefore525+4=529∴525+4=529Hence, the square root of 529 is 23.