Question

Find the least number which must be added to 525 to get a perfect square. Also find the square root of the perfect square.​

Answer 1

Step-by-step explanation:

$prime \: factor \: of \: 525 \\ = {3} \times {5}^{2} \times 7 \\ number \: we \: multiply \: to \: perfect \: square \\ = 3 \times 7 \\ perfect \: square = (3 \times 7 \times {5}^{2} ) \times (3 \times 7) \\ = {(3 \times 5 \times 7)}^{2} = {105}^{2} = 11025 \\ 11025 - 105 = 920 \: is \: added$