Question

Find the least number which must be added to 6412 to make it a prefect squre

Answer 1

Answer:

81

Step-by-step explanation:

We are given a number 6412.  

We have to find the least number which must be added to 6412 so as to get a perfect square and also square root of the perfect square.

Now, we think about the nearest perfect square number and compare with the given number.

The first two digits are 64 and it is a square of the number 8. It means the number at the tenth place of square root will be 8.

Now, we think about the unit place of the square root number.

Let the number at the unit place is 0.

If we square off the number 80, the answer will be 6400.

But it is less than the given number so this cannot be our number.

Let the number at the unit's place is 1.

If we square off the number 81, the answer will be 6561.

This number is greater than the given number. It means we have to subtract the given number from 6561 to get that value which can be added to the number 6412 to make it a perfect square.

Therefore, 6561−6412=149

Hence, 149 is the least number which must be added to 6412 so as to get a perfect square.

The required number is 6412+149=6561.

Now we evaluate the square root of the number 6561.

On factorisation, we get

6561−−−−√=3×3×3×3×3×3×3×3−−−−−−−−−−−−−−−−−−−−−−−√

Evaluate the square root. The numbers which are in the pair will come out from the square root.

That is,

 6561−−−−√=3×3×3×3

 

⇒6561−−−−√=81