Find the least number which must be added to each of the following numbers so as
to get a perfect square. Also find the square root of the perfect square so obtained
(1) 525
(i) 1750
(m) 252
(iv) 1825
(v) 6412
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Answer:
1)Smallest number that should be added to
525 to make it a perfect square is 4.
after adding 4, the number will become 529 whose square root is 23.
2) The smallest numbers to be added to 1750 is 14, 1750+14=1764
prime factorization of 1764, we get
√2²×3³×7²
= 2×3×7
42
√1764=42×42
3)Hence, 252 is not a perfect square.
:15'2<252<16'2
=225<252<256
the no. nearest to 252 is 256
So 256-252=4
4 should be added to 252 to be a perfect square.....
252+4=256
√256= 16×16
4) 42×42= 1764
this is smaller so will try with 43
43×43=1849
so,
1849-1825
=24
so 24 Will be added
5) nearest perfect square
80×80=6400
which is smaller.
so,
81×81=6516
so,
6561-6412=149
so the number is 149 to be added to 6412.
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