Question

find the least number which must be subtracted from 2311 to make it a perfect square​

Answer 1

$\Huge{\underline{\boxed{\blue{\mathfrak{ Answer }}}}}$

$\sf \hookrightarrow 7$

${\boxed{\blue{\mathfrak{ Solution :- }}}}}$

$\sf Start\ by\ taking\ the\ square\ root\ of\ 2311.\\\\\\\rightarrow \sqrt{2311} = 48.07286\\\\\\Now,\\\\48^{2} = 2304\\\\\\\\Subtracting\ the\ square\ from\ the\ original\ number\\\\2311 - 2304 = 7$