Find the least number which must be subtracted from 335250 so as to make it a perfect square also find the square root of the numbers so obtained
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1st individualise the numbers from right having 2 digits in every units.
now in the last unit the number is one's place is 0 so the possible value of one's olace of the square root is 0.
again in the 1st unit the nuber formed in the last two digit is 33 and the maximal value whose square is nearest to 33 is 5 whose square is 25.
now by hit and trail method find the possible value of square root
but its not a perfect square so its equivalent to 580
then its nearest perfect square is 579.
so 9 will be substracted from 335260
now in the last unit the number is one's place is 0 so the possible value of one's olace of the square root is 0.
again in the 1st unit the nuber formed in the last two digit is 33 and the maximal value whose square is nearest to 33 is 5 whose square is 25.
now by hit and trail method find the possible value of square root
but its not a perfect square so its equivalent to 580
then its nearest perfect square is 579.
so 9 will be substracted from 335260
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Nissikeerthana:
I too got same but I tried logically
Answered by
3
Answer:
1st individualize the numbers from right having 2 digits in every units.
now in the last unit the number is one's place is 0 so the possible value of one's place of the square root is 0.
again in the 1st unit the number formed in the last two digit is 33 and the maximal value whose square is nearest to 33 is 5 whose square is 25.
now by hit and trail method find the possible value of square root
but its not a perfect square so its equivalent to 580
then its nearest perfect square is 579.
so 9 will be substracted from 335260
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