Math, asked by Anonymous, 9 months ago

Find the least number which must be subtracted from 6203 to obtain a perfect square also find square root of the number by long division method


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Answered by joshiharshin
21

Answer:

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Answered by Anonymous
35

AnswEr :

78.

\bf{\red{\underline{\underline{\bf{Given\::}}}}}

The subtracted from 6203 to obtain a perfect square.

\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}

The square root of the number by long division method and also the least number.

\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}

\begin{array}{r|cccc} & 78\\ \cline{2-2} 7 & 6203\\+7&-49 &  & \\ \cline{2-2} 148&  1303 \\ & 1184 \\ \cline{2-5} \cline{2-2}& *119&\end{array}

We have get remainder = 119.

Then;

119 must be subtracted to get a perfect square.

\leadsto\sf{6203-119}\\\\\leadsto\sf{\red{6084}}

This is perfect square root = √6084 = 78.

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