Question

Find the least number which must be subtracted from 6203 to obtain perfect square .Also, find square root of the number so obtained.​

Answer 1

Step-by-step explanation:

To find the least number that must be subtracted from 6203 to obtain a perfect square, we will have to compute the square root of 6203 by Long Division method. So, the remainder is 119 and 119 is the least number that must be subtracted from 6203 to get a perfect square.

Answer 2

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cosA=5/13

sinA=-√(1-cos^2A) (since theta is in 4th quadrant)

i.e. sinA=-√144/169

=-12/13

tanB=-15/8

sinB=+(15)/√{(-15)^2+(8)^2} (B is in Q2)

i.e. sinB=15/17

cosB=tanB/sinB

i.e. cosB=-15/8 * 17/15

cosB=17/8

now

sin(A+B)=sinAcosB+cosAsinB

sin(A+B)=(-12/13)(17/8)+(5/13)(15/17)

={1/13}(-51/2 + 75/17)

=(1/13)(-710/34)

=-710/442

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