Question

Find the least number which must be subtracted from 6252 to make it a perfect square also find the square root of the perfect square so obtained.​

Answer 1

• We need to find the least number after subtracting which the resulting number is a perfect square.

• Clearly, (80)² > 6252 > (78)² ; one can see obviously that 6400 which is square of 80 is more than 6252, which in turn is more than square of 75 i.e. 5625.

• Now square of 79 = 79×79 = 6241

• So least number required = 6252 - 6241 = 11.

The square root of 6241 = 79.

You can also find the square root of 6252 first by long root method. You will get it as 79 with some decimal part. So, the nearest perfect square will be of 79.

Answer 2

Therefore , 11 must be subtracted from 6252 to make it perfect square.

$\sqrt{6241}= 79$

Step-by-step explanation:

                        _79_______

                         6252

                          49  

                           _____

                 149   |  1352

                              1341

                           _______

                                   11

Therefore , 11 must be subtracted from 6252 to make it perfect square.

∴The number become= (6252-11)= 6241

$\sqrt{6241}= 79$