Question

Find the least number, which must be subtracted from 7147 to make it a perfect square

Answer 1

Here is the answer of given problem

Answer 2

$Given \:number \: 7147$

$\underline {Find \: square \:root\: by \:division \: method}$

8 | 71 47 | 8

×8| 64

_________

164| 747 |4

× 4 | 656

__________

168 | 91

$The \: Remainder \: is \: 91$

$This \:means, \: if \: we \: subtract \:91 \: from \\7147, \: we \:get \: a \: perfect \:square .$

$Hence, \green { the \: required \:least \: number \: is \: 119 }$

Verification :

7147 - 91 = 7056

$7056 = 84^{2} \\\blue { ( Perfect \:square )}$

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