find the least number which must be subtracted from 787 so as it gets a perfect square, (Note:- The number so obtained is a perfect square of which number)
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Answers
We know that, if we subtract the remainder from the number, we get a perfect square.
Here, we get the remainder 2. Therefore 2 must be subtracted from 402 to get a perfect square.
\therefore402-2=400∴402−2=400
Hence, the square root of 400 is 20.
(ii) 1989
We know that, if we subtract the remainder from the number, we get a perfect square.
Here, we get the remainder 53. Therefore 53must be subtracted from 1989 to get a perfect square.
\therefore1989-53=1936∴1989−53=1936
Hence, the square root of 1936 is 44.
(iii) 3250
We know that, if we subtract the remainder from the number, we get a perfect square.
Here, we get the remainder 1. Therefore 1 must be subtracted from 3250 to get a perfect square.
\therefore3250-1=3249∴3250−1=3249
Hence, the square root of 3249 is 57.
(iv) 825
We know that, if we subtract the remainder from the number, we get a perfect square.
Here, we get remainder 41. Therefore 41 must be subtracted from 825 to get a perfect square.
\therefore825-41=784∴825−41=784
Hence, the square root of 784 is 28.
(v) 4000
We know that, if we subtract the remainder from the number, we get a perfect square.
Here, we get the remainder 31. Therefore 31 must be subtracted from 4000 to get a perfect square.
\therefore4000-31=3969∴4000−31=3969
Hence, the square root of 3969 is 63.
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