Question

Find the least number which must be subtracted from the 2361 to make it a perfect square​

Answer 1

we know square of 50 is 2500.

Then

(a-b)^2 = a^2 + b^2 -2ab

(50 - 1)^2 = 50^2 + 1^2 - 2*50*1

Square of 49= 2401

It is bigger than 2361 so we calculate for 48.

(a-b)^2 = a^2 + b^2 - 2ab

(50 - 2)^2 = 50^2 + 2^2 - 2*50*2

Square of 48 = 2304

This is smaller than 2361.

So

2361–2304=57

The smallest is 57 which is subtracted from 2361 so we will get 2304 perfect square of 48.

Thank you

Answer 2

Answer:

here is your answer -

Step-by-step explanation:

57 is the least number which must be subtracted from the 2361 to make it a perfect square.

2361 - 57

2304 is your answer

please subscribe my YouTube channel

useful channel