Math, asked by philippkunjappu1953, 1 day ago

Find the least number which on adding 10 is exactly divisible by 14, 35, 40, 56

Answers

Answered by bhumiudaipuria
3

Answer:

Prime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very grateful

Answered by aditya942raj
0

Answer:

Prime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very gratefulPrime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very gratefulPrime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very gratefulPrime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very gratefulPrime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very gratefulPrime factors

14= 2*7

35=5*7

40=2^3*5

56=2^3*7

LCM = 2^3*5*7 = 8*5*7=280

280 is the least no divisible by the given nos

Therefore 280-10=270 is the answer

Step-by-step explanation:

Hope it helps

if yes pls mark as brainliest I will be very grateful

Step-by-step explanation:

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