Question

Find the least number which on being divided by 5, 6, 8, 9, 12, leaves remainder 1 in each case, b
when divided by 13 leaves no remainder.​

Answer 1

Answer:

5

Step-by-step explanation:

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Answer 2

Answer:

3601

Step-by-step explanation:

we need to find the LCM of 5, 6, 8, 9 & 12

LCM is 360

multiples of 360 + 1 will give your answer

3601 = (5 × 720) + 1

3601 = (6 × 600) + 1

3601 = (8 × 450) + 1

3601 = (9 × 400) + 1

3601 = (12 × 300) + 1

3601 = (13 × 277) + 0

hope you get your answer