Question

Find the least number which on being divided by 8, 10 and 12 leaves a

Remainder 3 every time.
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Answer 1

Answer:

8.10.12.14

Step-by-step explanation:

8,10,12,14

Answer 2

Answer:

123

Step-by-step explanation:

According to the question,

First, we need to find the LCM of 8, 10, and 12 because LCM is the least number which on being divided by the numbers.

So,

LCM of 8, 10, and 12 is-

$8=2X2X2\\\\10=2X5\\\\12=2X2X3\\\\LCM=2X2X2X3X5\\\\LCM=8X15\\\\LCM=120$

if these numbers leave a Remainder 3 every time.

Then, we need to add 3 in the LCM of 8, 10, and 12.

So,

$120+3=123$

Hence, 123 is the least number which on being divided by 8, 10, and 12 leaves a Remainder 3 every time.