Math, asked by Chantan, 1 year ago

Find the least number which on decresing by 20 is exactly
divisible by 18,21,28 and 30

Answers

Answered by Terry1987

1

Answer:

1280

Step-by-step explanation:

LCM of 18, 21, 28 & 30=1260

18= 2x3x3

21= 3x7

28= 2x2x7

30= 2x2x5

The required number= 1260+20= 1280

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