Question

- Find the least number, which on dividing by 15, 20 and 40 leaves the remainder 4.​

Answer 1

$\huge\underline{\mathbb\red{❥︎A}\green{N}\mathbb\blue{S}\purple{W}\mathbb\orange{E}\pink{R}}\:$

LCM = 2x2x3x5x7 = 420. Next add 6 to 420 to get 426 as the answer. Check: 426/12 = 35 as quotient and 6 as remainder.

Answer 2

Step-by-step explanation:

the no dividing by 15, 20 and 40 is 129

hope it helps you buddy